x^2+15.2x+52=0

Solution for x^2+15.2x+52=0 equation:

x^2+15.2x+52=0

a = 1; b = 15.2; c = +52;
Δ = b2-4ac
Δ = 15.22-4·1·52
Δ = 23.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15.2)-\sqrt{23.04}}{2*1}=\frac{-15.2-\sqrt{23.04}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15.2)+\sqrt{23.04}}{2*1}=\frac{-15.2+\sqrt{23.04}}{2}
$